Question

Find the sum of all three digt numbers, which
leave 4 when divided by 5.​

Answer 1

Answer:

sum of all 3digit Nos. which leave 4 when divided

by 5 = 108270

Step-by-step explanation:

Sum of series = n/2 [ 2a + ( n -1 ) d ]

n = total numbers in series = 900/5 = 180

a = first number of series = 104

d = difference between two numbers = 5

sum = 180/2 [ 2 ×104 + ( 180 - 1) 5]

sum = 90 [ 208 + (199 ×5)]

sum = 90 ( 208 + 995)

sum = 90 × 1203

sum = 108270