Question

find the sum of all three terms of AP whose middle most term is 30

Answer 1

Step-by-step explanation:

Given middle term or the sixth term is 30

Given middle term or the sixth term is 30 Then, a+5d=30

Given middle term or the sixth term is 30 Then, a+5d=30 sum=n/2(2a+(n-1)d)

Given middle term or the sixth term is 30 Then, a+5d=30 sum=n/2(2a+(n-1)d)= 11/2(2a+10d)

Given middle term or the sixth term is 30 Then, a+5d=30 sum=n/2(2a+(n-1)d)= 11/2(2a+10d)=11/2(2×30)

Given middle term or the sixth term is 30 Then, a+5d=30 sum=n/2(2a+(n-1)d)= 11/2(2a+10d)=11/2(2×30)=330