Find the sum of all two didit odd multiples of 3
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The AP will be:
15,21,27...99
an=a+(n-1)d
99=15+(n-1)6
99=15+6n-6
99=9+6n
6n=90
n=15
Now, Sn=n/2(a+l)
So,
Sn=15/2(15+99)
Sn=15/2(114)
Sn=57×15
Sn=855
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2d odd multiples of 3
12
15
18
21
24
27
30
33
36
39
42
45
48
51
54
57
60
63
66
69
72
75
78
81
84
87
90
93
96
99
Sum=9387
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