Find the sum of all two digit natural no which are divided by 4
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0
Answer:
1188(sum of all two digit natural number)
Answered by
2
Answer:
1188
Step-by-step explanation:
12,16,........,96
a=12
d= 16-12 = 4
t=96
t= a +(n-1)d
96= 12 +(n-1)4
n=22
sum of n digits no. is
S = n/2 [2a+(n-1)d]
S= 22/2[2×12+(22-1)4]
S=11(24+108)
S= 1188
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