find the sum of all two digit natural number which are divisible by 3
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Req. Two digits no.'s are 10,13,16,17....97 d= 3 ,a=10 and l= 97 an = a+(n-1)d 97-10=(n-1) 3 29=n-1n = 30 Sn = n/2(a+l) =30/2(10+97) S=15(107)= 1605
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