Find the sum of all two digit natural numbers which are divisible by 5
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Answer:
Step-by-step explanation:
10,15.........95
L=a+(n-1)d
95=10+(n-1)5
85=5n-5
90=5n
n=18
Sum
Sn=n/2(a+l)
S18=18/2(10+95)
S18=9*105
945 is the answer
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