find the sum of all two digit no. whose sum of digits is divisible by 7 and the no. is divisible by 3
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Answer:
The two digit number which gives a remainder of 3 when divided by 7 are:
10, 17, 24 ..... 94.
Now, these number are in AP series with
1st Term, a = 10;
Number of Terms, n = 13;
Last term, L = 94 and
Common Difference, d = 7.
Sum,
= {n*(a+L)/2}
= 13*52 = 676.
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