Question

find the sum of all two digit number which when divided by 5 leaves remainder 1​

Answer 1

Answer:

6 (approx)

Step-by-step explanation:

I think · It is the number of particles in a single mole of a material, based on the number of atoms in exactly 12 grams of the isotope carbon-12. Although this number is a constant, it's experimentally determined, so we use an approximate value of 6.022 x 1023.

Answer 2

Step-by-step explanation:

let n be the integer which when divided by 5 leaves remainder 1

therefore ,n-1 is divisible by 5

=>n-1=5k,k belongs to integer

=>n=1+5k

according to question

9<n>100 ( since n is a two digit number)

i.e. 9<1+5k>100

i. e. 8<5k>99

from this we obtain the value of k as

k=2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18 and19

therefore, n=10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95

Sn=18/2{10+95}

=9x105

=945