find the sum of all two digit numbers
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Answer::
Sn = n/2 [a+l]
first 2 digit number (a) = 10, last number(l) = 99, no.of digits from 10 to 99 = 90
Sn = 90/2 [10+99]
Sn = 45(109)
Sn = 4905
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