Math, asked by Fatmi, 1 year ago

Find the sum of all two digit numbers

Answers

Answered by krishnakant8544
3

there u are... 4905

Attachments:

solankiji479: If we add 1st of last it will 110 an 2nd and last secong agin come 110
krishnakant8544: boss.. i hv done it right.. u can check it..
geetamadavi1234: Yes it is correct
Answered by geetamadavi1234
1

Here is your solution:-

The two digit numbers are :-

10,11,12,...........99

Now it is clear that the given sequence is in AP with difference of 1

So, a=10 ; d=1 & an= L = 99

Therefore,

an = a + (n-1)×d

99= 10 + (n-1)×1

99-10=n-1

89=n-1

n=89+1

n=90

So there are total 90 two digit numbers

Now,

Sn=n/2(a+L)

S20= 20/2(10+99)

S20=10(109)

S20 = 1090

Therefore the sum of all two digit numbers is 1090.---(Answer)

Thanks for asking this question

Please mark it as a brainly answer


geetamadavi1234: Sorry it's wrong
geetamadavi1234: I have to take S90
geetamadavi1234: But I took S20
geetamadavi1234: The correct answer is
geetamadavi1234: S90 = 90/2 (10+99)
geetamadavi1234: S90 = 45 × 109
geetamadavi1234: S90 = 4905
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