Find the sum of all two-digit numbers which when divided by 3 leaves 1 as remainder.
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Req. Two digits no.'s are 10,13,16,17....97
d= 3 ,a=10 and l= 97
an = a+(n-1)d
97-10=(n-1) 3
29=n-1
n = 30
Sn = n/2(a+l)
=30/2(10+97)
S=15(107)= 1605
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