Question

Find the sum of all two positive integer which are divisible by 4

Answer 1

Answer:

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Here's your answer...

Step-by-step explanation:

The two digit numbers divisible by 4 are:

12,16,20,.....96

So, a=12 and d=16-12=4

an = a+(n-1)d

96 = 12+ (n-1)4

96-12= 4n-4

4n= 88

n=22

Sn = n/2[ 2a+(n-1)d]

Sn = 22/2 [2×12+(22-1)4]

Sn= 11×108= 1188

Hope it helps you ✌

Answer 2

Answer:

let the sum be x

hence positive integers be

4 and 8 they both are positive integers and are also divisible by 4

therfore your answer would be

4+8=12

therfore your answer would be 12

hope this helps u

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