find the sum of alll integers between 50 and 500
Answers
Answered by
0
Answer:
use A. P
let's a=51,common difference =1, and last term =499
from that you find
second method
we know that the sum of nature numbers formula = n(n+1)/2
use it
Step-by-step explanation:
find the sum of 499 natural numbers first
which is 500*499/2
250*499
then find the sum sum of first 50 integers
= 50*51/2=25*51
so the required answer = 250*499-25*51
=123475
please note that in the above question 50 and 500 not included
Answered by
0
Answer:
Step-by-step explanation:
simplest way
500-50=450
450× 450=202500
hope that helps you dear
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