Find the sum of an A.P. 9,7,5, 3 ............ to 14 terms.
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Answered by
2
Answer:
a = 9
d = 7-9= -2
n = 14
S14 = 14/2[2×9 + (14-1)-2]
= 7(18 + 13×-2)
= 7(18 - 26)
= 7(-8)
= -56
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Answered by
4
Answer:
Sum of first 14 terms of this AP is -56.
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