find the sum of an arithmetic sequence iwith 49 terms if thr first term is -14 and the common difference is 23
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Given that,
the first term, t1 = (- 14)
and the common difference, d = 23
So, the sum of the Arithmetic sequence upto n = 49 terms
= n/2 × {2 t1 + (n - 1)d}
= 49/2 × [{2 × (- 14)} + {(49 - 1) × 23}]
= 49/2 × (- 28 + 48 × 23)
= 49/2 × (- 28 + 1104)
= 49/2 × 1076
= 26362
#MarkAsBrainliest
Given that,
the first term, t1 = (- 14)
and the common difference, d = 23
So, the sum of the Arithmetic sequence upto n = 49 terms
= n/2 × {2 t1 + (n - 1)d}
= 49/2 × [{2 × (- 14)} + {(49 - 1) × 23}]
= 49/2 × (- 28 + 48 × 23)
= 49/2 × (- 28 + 1104)
= 49/2 × 1076
= 26362
#MarkAsBrainliest
Answered by
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26362 is a correct answer
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