find the sum of angle of triangle is 180 the angle of a triangle are (x-40) , (x-20) , (x/2-10). find the value of x and then the angle of triangle.
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Hello Dear!!!!
Here's your answer...
Given,
Angles are (x-40) , (x-20) , (x/2-10)
Sum of these angles is 180
x-40+x-20+x/2-10 = 180
2x-70+x/2 = 180
2x+x/2 = 180+70
4x/2 + x/2 = 250
5x/2 = 250
5x = 500
x=100
angles are
x-40 = 100-40 = 60
x-20 = 100-20 = 80
x/2 - 10 = 50-10 = 40
angles are 60,80,40
________________________________________
hope this helps you....
Here's your answer...
Given,
Angles are (x-40) , (x-20) , (x/2-10)
Sum of these angles is 180
x-40+x-20+x/2-10 = 180
2x-70+x/2 = 180
2x+x/2 = 180+70
4x/2 + x/2 = 250
5x/2 = 250
5x = 500
x=100
angles are
x-40 = 100-40 = 60
x-20 = 100-20 = 80
x/2 - 10 = 50-10 = 40
angles are 60,80,40
________________________________________
hope this helps you....
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