Question

Find the sum of angles of the pentagon ABCDE.​

Answer 1

Answer:

${ \huge\fbox \pink {♥}\fbox \blue {A} \fbox\purple {N} \fbox \green{S} \fbox \red {W} \fbox \orange {E} \fbox{R} \fbox \gray{♥}}$

- Sum of interior angles of pentagon ABCDE = (n-2)×180° = (5 - 2)x180° = 540°.: sum of all angles of a pentagon is

5400

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Answer 2

Answer:

Sum of interior angles of pentagon ABCDE = (n-2)×180° = (5 - 2)x180° = 540°.: sum of all angles of a pentagon is

5400