find the sum of ap 2 , 5 , 8 ............, 182
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Answer:
This is an A.P
d = 3
a = 2
Tn = 182
Tn = (a+ (n-1)d)
182=(2+3n-3)
182=3n-1
3n = 183
n= 61
Sn = n (2a+(n-1)d)
2
Sn= 61 (4+60*3)
2
Sn = 61*184
2
Sn = 5612
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