find the sum of AP
(I) 2,4,6....,n terms
Answers
Answer:
don't know this answer so sorry
Step-by-step explanation:
First term of the given arithmetic series = 2
Second term of the given arithmetic series = 4
Third term of the given arithmetic series = 6
Fourth term of the given arithmetic series = 8
Now, Second term - First term = 4 - 2 = 2
Third term - Second term = 6 - 4 = 2
Therefore, common difference of the given arithmetic series is 2.
The number of terms of the given A. P. series (n) = 15
We know that the sum of first n terms of the Arithmetic Progress, whose first term = a and common difference = d is
S
n
=
2
n
[2a+(n−1)d]
S
15
=
2
15
[2×2+(15−1)2]
S
15
=7.5[4+28]
S
15
=240
Answered By
toppr
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