find the
sum of AP
of first
25 terms of A.P
3,6,9,12,15
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0
Answer:
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Answered by
0
Answer:
975
Step-by-step explanation:
a (first term)= 3
n (total no. of terms)= 25
d (common difference) = 6-3 = 3
an= a+(n-1)d
a25 = 3+(25-1)×3= 3+24×3 = 3+ 72 =75
Sn = n (a+an) ÷2 = 25(3+75) ÷2 = 25 ×78 ÷2 = 25×39 = 975
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