Question

Find the sum of ap (x-y)^2,(x^2+y^2),(x+y)^2,...To n terms

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

Since the A.P is ( x - y )2 , ( x2 + y2 ) ,

( x+y )2...............

1st term = ( x - y )2

common difference = ( x2 + y2 ) - ( x - y )2

x2 + y2 - ( x2 + y2 -2xy)

x2 + y2 - x2 - y2 + 2xy

therefore common difference = 2xy

Now we have to find sum of nth term.......

therefore Sn = (n/2)(2( x - y )2 + ( n - 1 ) * 2xy)

(n/2) * 2 * {( x - y )2 + ( n - 1 ) * xy ) }

n* ( x2 + y2 - 2xy + xyn - xy )

therefore the sum of nth term = n * ( x2 + y2 - 3xy +xyn ) or n * ( x2 + y2 - xy ( 3 - n ) )

Hope it helps you...