Question

find the sum of APs
1/15, 1/12,1/10... to 11 terms.​

Answer 1

Answer:

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Step-by-step explanation:

Sum of n terms of AP formula:

S  

n

​  

=  

2

n

​  

[2a+(n−1)d] ......(1)

Where

First term =a

Common difference=d

Number of terms=n

1/15,1/12,1/10,..... to 11 terms

a=1/15

d=(1/12)−(1/15)=1/60

Using (1)

S  

11

​  

=11/2[2(1/15)+(11−1)(1/60)]

=(11/2)×[(2/15)+(1/6)]

=33/20

Sum of 11 terms of this AP is 33/20

Answer 2

56/2 ,t20/Jio,not known

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