Question

find the sum of ARITHMETIC PROGRESSION

4O+37+34+.......+(-107)​

Answer 1

here is ur solution.........

Answer 2

a = 40

d = 37 - 40 = -3

l = -107

l = a + (n - 1) d

-107 = 40 + (n - 1)(-3)

-107 - 40 = -3(n - 1)

-147 = -3(n - 1)

-147/-3 = n - 1

49 = n - 1

n = 49 + 1

n = 50

Sn =

$= \frac{n}{2} (a + l)$

$= \frac{50}{2} (40 - 107)$

$= 25( - 67)$

$= - 1675$

Be Brainly!!!