Question

Find the sum of bases of that trapezium, whose prependicular is 11cm and area is o.55 square meter.

Answer 1

Step-by-step explanation:

The sum of base of that trapezium whose perpendicular is 11 cm is 10 m

Step-by-step explanation:

Height of trapezium = 11 cm = 0.11 m

Area of trapezium =\frac{1}{2} (\text{Sum of parallel sides}) \times height21(Sum of parallel sides)×height

                              =\frac{1}{2} (\text{Sum of parallel sides}) \times 0.1121(Sum of parallel sides)×0.11

Area is 0.55 square metre

So,\frac{1}{2} (\text{Sum of parallel sides}) \times 11 = 0.5521(Sum of parallel sides)×11=0.55

\text{Sum of parallel sides}= \frac{0.55 \times 2}{0.11}Sum of parallel sides=0.110.55×2

\text{Sum of parallel sides}=10 mSum of parallel sides=10m

Hence the sum of base of that trapezium whose perpendicular is 11 cm is 10 m

#Learn more:

Find the altitude of a Trapezium is the sum of the length of whose base is 6 cm and the area is 5.25 CM square

Answer 2

Answer:

5 × 2 = 10

Step-by-step explanation:

area is 0.55 m = 55 cam

h = 11 cm

1/2( sum of bases) × h = 55

1/2(sum of bases) × 11=55

sum of bases = (55 × 2)/11= 11 cut by 55 comes 5

so sum = 5 × 2=10