Question

Find the sum of complete square between 100 and 200

Answer 1

2308350

Step-by-step explanation:

Sum of squares of First N natural numbers = (n(n+1)(2n+1))/6

First calculate Sum of squares from 1 to 200 = 200(201)(401)/6 = 2686700

Secondly calculate Sum of squares from 1 to 100 = 338350

Now ,we need (1 to 200)^2 - (1 to 100)^2 = 2348350

given between 100 to 200

so,exclude 200^2 = 40000

2348350-40000 = 2308350