Question

find the sum of consecutive cubes up to 12³ ?​

Answer 1

Step-by-step explanation:

sum of consecutive cubes up to 12³ = 1³+2³....+12³

=

$= \frac{n ^{2} (n + 1) ^{2} }{4}$

$= \frac{ {12}^{2} \times {13}^{2} }{4}$

$= 6084$