Math, asked by aradhana2009, 2 months ago

Find the sum of consecutive natural numbers from 1 to 45​

Answers

Answered by ItzSiddhi3009
5

Answer:

1035

1+2+3+…….+45 , here first term a = 1 , last term l= 45 , total number of terms n = 45 , so the sum S = n/2 {a+l} = 45/2 {1+45}= 45*23 =1035

We can also conclude the same result with the formula of the sum of the first n natural number , i.e

We can also conclude the same result with the formula of the sum of the first n natural number , i.eS = n(n+1)/2 = 45(45+1)/2 =45*23=1035

Step-by-step explanation:

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Answered by prabhakarrmore58
0

Answer:

The number series 1,2,3,4......,44,45

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