Question

find the sum of cubes of first
ten natural numbers​

Answer 1

Answer:

Sum of the cube of first ten natural numbers :

.i.e., 1^3 + 2^3 + 3^3 + _ _ _ _ +10^3

We know the sum of cubes of ( n ) natural numbers ( S ) = { n ( n + 1 ) / 2 }^2

Here n = 10

Therefore , the sum of cubes of first 10 natural numbers + { 10 ( 10+ 1 ) / 2 }^2

= {10 x 11 / 2 } ^2

= {110 / 2 }^2

= ( 55 )^2

= 3025

Answer 2

1

${1}^{3} = 1 \\ {2}^{3 } = 8 \\ {3}^{3} = 27 \\ {4}^{3} = 64 \\ {5 }^{3} = 125 \\ {6}^{3 } = 216 \\ {7}^{3} = 343 \\ {8}^{3} = 512 \\ {9}^{3} = 729 \\ {10}^{3} = 1000$