Find the sum of deviations of all observations of the data 5,8,10,15,22from their mean.
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Answered by
135
mean = (sum of the observations)/number of observations
mean = (5+8+10+15+22)/5
= 60/5
mean=12
sum of the deviations = (5-12)+(8-12)+(10-12)+(15-12)+(22-12)
=-7-4-2+3+10
=-13+13
=0
mean = (5+8+10+15+22)/5
= 60/5
mean=12
sum of the deviations = (5-12)+(8-12)+(10-12)+(15-12)+(22-12)
=-7-4-2+3+10
=-13+13
=0
Answered by
36
Sum of observation = 5+8+10+15+22
=60
No.of observations = 5
Mean = 60 / 5 = 12
Sum of deviations of observations
= (5-12) +(8-12)+(10-12)+(15-12)+(22-12)
=-7-4-2+3+10
=-13+13
=0
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