find the sum of divisors od 544 which are perfect square
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544=2x2x2x2x2x17
i.e. the divisors of 544 are 2,4,8,16,32,17,34,68,136,272 and 544 of which 4 and 16 are perfect squares and their sum=4+16=20
i.e. the divisors of 544 are 2,4,8,16,32,17,34,68,136,272 and 544 of which 4 and 16 are perfect squares and their sum=4+16=20
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20 is the answer......
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