find the sum of each arithmetic sequence with the given condition
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Step-by-step explanation:
given that _
a1 = 3 An = 99 d = 3
a to q _
an = a +(n-1) d
99 = 3+ nd- d
99 = 3 + n× 3 - 3
99-3 + 3= 3n
102-3= 3n
99 = 3n
n= 11
then we find the sn of Ap , l = an
sn = n/2 ( a+l)
sn = 11 /2 ( 3+99)
sn = 11/2 × 102
sn= 11 × 51 = 561 ans.
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