Question

Find the sum of each of the following Ap 1/15, 1/12, 1/10 to 11 terms​

Answer 1

$\huge \mathbb \red{ ANSWER}$

$\tt{ \huge{ \underline{ \boxed{ \blue{ \tt{ \frac{33}{20 \: }}}}}}}$

__________________________________

$\sf \huge \underline{Question}$

Find the sum of each of the following Ap 1/15, 1/12, 1/10 to 11 terms

__________________________________

$\sf \huge \underline{To \: find}$

the sum of each of the following Ap 1/15, 1/12, 1/10 to 11 terms

$\sf \underline{step \: by \: step \: explanation}$

$\bf \underline \red{Given}$

ap is

$\rm{ \frac{1}{15}, \frac{1}{12} , \frac{1}{10}}........$

___________________________________

$\tt \huge \underline\blue{here}$

$\sf \red{a = \frac{1}{15}}$

$\sf \pink{d = \frac{1}{12} - \frac{1}{15}}$

$\sf \pink{ = \frac{5 - 4}{60}}$

$\sf \pink{ = \frac{1}{60}}$

__________________________________

$\bf \red{⟹ \: do \: u \: know \: formula}$

$\bf{ \underline{ \boxed{ \green{ \tt{Sn = \frac{n}{2}[2a + (n - 1)d] \: }}}}}$

$\tt \orange{⟹s11 = \frac{11}{2} =[2 \times [ \frac{1}{15} ] + (11 - 1) \times \frac{1}{60}]}$

$\tt \pink{⟹ \: \frac{11}{2} \times [ \frac{2}{15} + \frac{10}{60} ]}$

$\tt \blue{⟹ \: \frac{11}{2} = [ \frac{18}{60} ]}$

$\tt \red{⟹ \: = \frac{33}{20}}$

I hope it's help uh