Question

Find the sum of even numbers between 0 to 50
solution:
2,4,6,8.........48
a=2
d=2
an=48
n=?
sn=?
an=a+(n-1)d
48=2+(n-1)2
48=2+2n-2
n=48/2
n=24
sn=n/2(2a+(n-1)d)
sn=24/2(2.2+(24-1)2)
=12(4+46)
=12(50)
sn=600
​

Answer 1

Step-by-step explanation:

yes it's the correct answer

Answer 2

Given; 2, 4, 6 8 are the given numbers

To Find; Sum of even numbers between 0 to 50

Solution; even numbers 1, 2, 4, 6 and do on

The last number is 48

a1= 2, a 2= 4,d =a2 - a1 = 4-2 = 2,n=?

the sum of even numbers can be calculated using ap

an =a + (n-1) d

48 = 2+ (n-1)2

46 = (n-1)2

23 = n-1

24 = n

Sum of even terms

Sn = n (2a +(n-1)d)/2

12(2*2+23*2)

12(4+46)

12(50)

600

Hence the sum of even numbers is 600