find the sum of first 09 terms in given A.P 0.9, 0.7, 0.5
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Answer:
S9=n/2(2a+(n-1)d)
a=0.9. d=0.-2
9/2(2*0.9+(9-1)*-0.2
9/2(1.8+(8*2/10)
9/2(1.8+8/5)
9/2*(18/10+8/5)
9/2(9/5+8/5)
9/2*13/5=
117/10
11.7. Answer
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