Find the sum of first 10 and first 15 terms of AP:1/15,1/12,1/10....
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Answer:
Step-by-step explanation:
a=1/15
d=1/12-1/15=5-4/60=1/60
n=10
Sn=n/2(2a+(n-1)d)
S10=10/2(2×1/15+9×1/60)
=5(2/15+3/20)
=5(8+3/60)
=5×11/60
=11/12
n=15
S15=15/2(2×1/15+14×1/60)
=15/2(2/15+7/30)
=15/2(4+7/30)
=15/2(11/30)
=11/4
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