Question

find the sum of first 10 multiples of 3​

Answer 1

Sum of 10 multiples of 3 ,

a = 3,

d = 3,

n = 10,

S10 = ?,

To find S10 -

Sn = n/2 (2a + (n - 1) d )

= 10/2 (2 x 3 + (10 -1) 3)

= 5 (6 + 9 x 3)

= 5 (6 + 27)

= 5 x 33

= 165

Sum of first 10 multiples of 3 is 165.

Answer 2

Answer:

hi.......

here's the answer:

series=

3,6,9,........30

a = 3 ; d = a 2 -a 1 = 6 - 3 = 3 ; n = 10

S = n/2 ( 2 a + ( n - 1 ) d )

S = 10/2 ( 2(3) + ( 10 - 1 ) 3 )

S = 5 ( 6 + ( 9 ) 3 )

S = 5 ( 6 + 27 )

S = 5 ( 33 )

S = 165

#hope this helped u

Step-by-step explanation: