Find the sum of first 10 multiples of 4
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Given:
First 10 multiples of 4
To find:
The sum of the given multiples
Solution:
The required sum is 220.
We can obtain the sum's value by adding the given multiples of 4.
We can have the multiples by multiplying 4 with 1, 2, 3, and so on till 10.
The multiples given are as follows-
4, 8, 12, 16, 20, 24, 28, 32, 36, 40.
This forms a progression with first term=4, last term=40.
So, the required sum=N/2(A+L), where N is the total multiples, A is the first term and L is the last term.
Using the values,
Sum=10/2(4+40)
=5×44
=220
Therefore, the required sum is 220.
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