Question

find the sum of first 10 multiples of 5​

Answer 1

Let a=5

An=50

Sn=n/2(2a+(n-1)d)

=>10/2(2x5+(5-1)5)

=> 5(10+20)

=>5x30

=>150.

Ans!!

Answer 2

Answer:

275 is the sum of the first 10 multiples of 5.

Step-by-step explanation:

To find:-

The sum of the first $10$ multiples of 5.

Step 1 of 1

Consider the series of the 10 multiples of 5 as follows:

5 + 10 + 15 + . . . + 50

Here,

The first term, a = 5

The common difference, d = 5

The number of terms, n = 10

As we know,

The sum of n terms of a sequence is,

$S_n=\frac{n}{2} (2a+(n-1)d)$

Substitute the all the required values as follows:

$S_{10}=\frac{10}{2} (2(5)+(10-1)5)$

$S_{10}=$ 5(10 + 9(5))

$S_{10}$ = 5(10 + 45)

$S_{10}$ = 5(55)

$S_{10}$ = 275

Therefore, 275 is the sum of the first 10 multiples of 5.

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