Find the sum of first 10 multiples of 6
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330
Answers
Answered by
27
Answer:
330
Step-by-step explanation:
First 10 multiples of 6 are :
6 , 12 , 18 ... 54 , 60.
Here,
- a = first term = 6
- d = common difference = 6
Now,
We know the formula that :
Sn = n / 2 [ 2a + (n - 1) d ]
To find the Sum of 10 terms,
S10 = 10 / 2 [ 2 × 6 + ( 10 - 1 ) × 6 ]
S10 = 5 × [ 12 + 54 ]
S10 = 5 × 66
S10 = 330
Thus,
We got the sum as 330.
Sum of first 10 multiples of 6 is 330.
__________________________
Answered by
1
Answer:
330
Step-by-step explanation:
6+12+18+.........+60
=6*(1+2+3+..........+10)
=6*10*11/2 ( Sum of no 1 to 10=10*11/2)
=6*5*11
=330
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