Question

Find the sum of first 10 natural no​

Answer 1

Answer:

use this formula put 10 in x

$x(x + 1) \div 2$

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Answer 2

Answer:

Natural number's are 1,2,3,.....

a= 1

d=1

$S_{n} = \frac{n}{2} [2a+(n-1)d]\\= \frac{10}{2} [2(1)+(9)1]\\\\=5[ 2+9]\\= 5(11)\\=55$

∴ The sum of the 1st 10 natural numbers is 55