Question

find the sum of first 10 natural numbers?​

Answer 1

Step-by-step explanation:

Sumoffirstnnaturalnumbers=

2

n(n+1)

\begin{gathered} Here, n = 10\\ < /p > < p > Now,\\Sum \: of \: first \: 10 \: natural\: numbers\\=\frac{10(10+1)}{2}\\=\frac{10\times 11}{2}\\=5\times 11\\=55\end{gathered}

Here,n=10

</p><p>Now,

Sumoffirst10naturalnumbers

=

2

10(10+1)

=

2

10×11

=5×11

=55

Therefore,

Sum \: of \: first \: 10 \: natural\: numbers=55Sumoffirst10naturalnumbers=55

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Answer 2

Answer:

Sum of first 10 natural numbers is 45