Question

find the sum of first 10 odd prime numbers Of an A.P​

Answer 1

Answer:

a=1, n=10, d=2, S10=?

S10=n/2[2a+(n-1) d]

=10/2[2×1+(10-1) 2]

=5[2+18]

=5×20

=100

hence sum of first 10 odd numbers is 100