Question

find the sum of first 10 term of geometric series square root 2+ square root 6+ square root 18+..​

Answer 1

Step-by-step explanation:

The GP is given by √2,√6,√18,...

First term, a=√2

Common ratio, r=√3

No. of terms, n=10

Sum of GP, S₁₀=a(rⁿ-1)/(r-1)

                        =√2[(√3)¹⁰-1]/[√3-1]

                        =242√2/(√3-1)

You can rationalize the denominator for a more presentable answer.