Question

Find the sum of first 10 terms of 7 ,13, 19​

Answer 1

Answer:

n/2 x1+xm

{68*5)

that is 340

Answer 2

Answer:

Firstly we have to find the nth term

so formula is a+(n-1)d

a=7,d=6

so nth term is 7+(10-1)6

7+54=61

so now sum of term

S10=n/2(a +an)

10/2(7+61)

5*68=340

340 is the answer i.e. the sum