Question

Find the sum of first 10 terms of the A.P.
4+6+8+.........

Answer 1

an = a+(n-1)d.....(1)

a = 4, d= 6-4=2

n= 10

put in (1)

a10= 4+(10-1)2

a10= 4+18=22

Sn = n/2[a+an]

S10= 10/2[4+22]

S10= 5[ 26] =130

sum for first ten terms is 130

Answer 2

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