find the sum of first 10 terms of the A.P . 4+6+8........
Ans = 130
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a=4
n=10
d=6-4=2
formula= Tn=n/2[a+(n-1)d]
=> 10/2[4+(10-1)2]
=> 5[4+9×2]
=>5[13×2]
=>5×26
=> 130
n=10
d=6-4=2
formula= Tn=n/2[a+(n-1)d]
=> 10/2[4+(10-1)2]
=> 5[4+9×2]
=>5[13×2]
=>5×26
=> 130
jinse74:
thanks bro
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