Find the sum of first 10 terms of the A.P. : 8 , 4 , 0 , -4 , -8 , ..................
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Answer:
- 100 = sum of 10 terms of given A.P.
Step-by-step explanation:
Given:
A.P. : 8 , 4 , 0 , -4 , -8 , .......
TO FIND :
the sum of first 10 terms
Formula used:
Common difference (d) = second term - first term (a)
Tn (nth term) = a + (n-1)d
Sn ( sum of n terms) = n/2( 2a + (n-1)d) or Sn= n/2 (a + l ) (where l is last term )
Solution:
d = second term - first term (a)
d = 4-8
d= -4
a = 8
Tn=a + (n-1)d
T10 = 8 + (9-1) (-4)
T10= 8 - 36
T10= - 28
therefore 10th term is -28
Sn= n/2 (a + l ) (where l is last term )
s10= 5 ( 8 + (-28) )
s10 = 5 ( - 20)
s10 = -100
Alternate method of finding sum ( another formula) :-
Sn = n/2( 2a + (n-1)d)
s 10 = 5 ( 16 + 9 ( -4) )
s10 = 5 ( 16 - 36 )
s10 = 5 * (-20)
s10 = -100
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