Find the sum of first 10 termsof an AP :31,26,21,16
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Answer:
85
Step-by-step explanation:
Sn=n/2[2a+(n-1)d]
=10/2[2(31)+(10-1)-5]
=5[62-45]
=85
d is -5 because 26-35=-5
Hope it helps
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