Math, asked by bbbhffhnnnb, 2 months ago

find the sum of first 100 even natural nos.​

Answers

Answered by THARIKASHANMUGARAJ
0

Answer:

step 1 Address the formula, input parameters & values.

Input parameters & values:

The number series 2, 4, 6, 8, 10, 12, . . . . , 200.

The first term a = 2

The common difference d = 2

Total number of terms n = 100

step 2 apply the input parameter values in the AP formula

Sum = n/2 x (a + Tn)

= 100/2 x (2 + 200)

= (100 x 202)/ 2

= 20200/2

2 + 4 + 6 + 8 + 10 + 12 + . . . . + 200 = 10100

Therefore, 10100 is the sum of first 100 even numbers.

Answered by ammarkhan49
0

Answer:

10100

Step-by-step explanation:

The number series 2, 4, 6, 8, 10, 12, . . . . , 200.

The first term a = 2

The common difference d = 2

Total number of terms n = 100

Sum = n/2 x (a + Tn)

= 100/2 x (2 + 200)

= (100 x 202)/ 2

= 20200/2

2 + 4 + 6 + 8 + 10 + 12 + . . . . + 200 = 10100

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