Question

Find the sum of first 100 even natural
numbers.​

Answer 1

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Answer 2

Answer: 10100

Step-by-step explanation:

The even Natural numbers are 2,4,6,8,10..............

As it forms an AP whose first term a = 2 , common difference d =2

Given in question n =100

Now as we know sum of n terms of an AP is

$S_{n} =\dfrac{n}{2} (2a+(n-1)d)$

Therefore

$S_{100} =\dfrac{100}{2} (2*2+(100-1)2)$

        =50(4+99*2)

        = 50(202)

        =10100

Therefore the sum of first 100 even natural numbers is 10100